7(4z^2-2y^2)=

Solution for 7(4z^2-2y^2)= equation:

Simplifying
7(4z2 + -2y2) = 0

Reorder the terms:
7(-2y2 + 4z2) = 0
(-2y2 * 7 + 4z2 * 7) = 0
(-14y2 + 28z2) = 0

Solving
-14y2 + 28z2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-28z2' to each side of the equation.
-14y2 + 28z2 + -28z2 = 0 + -28z2

Combine like terms: 28z2 + -28z2 = 0
-14y2 + 0 = 0 + -28z2
-14y2 = 0 + -28z2
Remove the zero:
-14y2 = -28z2

Divide each side by '-14'.
y2 = 2z2

Simplifying
y2 = 2z2

Take the square root of each side:
y = {-1.414213562z, 1.414213562z}